单片机加矩阵按键控制蜂鸣器唱歌，按一下一个键是前一首，另一个是后一首，还有一个按键是用来控制的
#include
#include
#define uchar unsigned char
#define uint unsigned int
uchar Song_Index = 0,Tone_Index = 0;
sbit SPK = P3^7;
sbit K1 = P1^0;
uchar code DSY_CODE[]=
{
0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90
};
uchar code HI_LIST[]=
{
0,266,229,232,233,236,238,240,241,242,244,245,246,247,248
};
uchar code LO_LIST[]=
{
0,4,13,10,20,3,8,6,2,23,5,26,1,4,3
};
uchar code Song[][50]=
{
{1,2,3,1,1,2,3,1,3,4,5,3,4,5,3,4,5,5,6,1,2,3,6,2,6,6,2,3,4,5,2,5,2,3,-1},
{3,3,3,5,6,2,3,4,6,2,6,4,2,1,2,3,6,2,5,6,3,4,5,6,2,3,1,2,3,5,1,2,3,-1},
{3,2,1,3,2,1,1,2,3,1,3,5,1,5,4,6,2,6,3,4,2,3,6,2,3,4,2,1,1,1,2,2,2,3,3,2,6,3,5,3,5,1,2,6,4,5,-1}
};
uchar code 运宴Len[][50]=
{
{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,1,1,2,2,2,2,2,2,2,2,2,2,2,1,1,-1},
{1,1,1,1,1,1,1,1,1,1,1,2,2,1,1,1,2,2,2,2,1,1,1,1,1,1,1,1,-1},
{1,1,2,1,1,2,1,1,1,1,1,1,1,1,2,1,1,1,2,1,1,1,1,1,1,1,2,1,2,1,2,1,2,1,1,1,1,1,2,2,-1}
};
void EX0_INT() interrupt 0
{
TR0 = 0;
Song_Index = (Song_Index+1)%3;
Tone_Index = 0;
P2 = DSY_CODE[Song_Index];
}
void T0_INT() interrupt 1
{
SPK = !SPK;
TH0 = HI_LIST[Song[Song_Index][Tone_Index]];
TL0 = LO_LIST[Song[Song_Index][Tone_Index]];
}
void delay(uint ms)
{
uchar i;
while(ms--)
{
for(i=0;i<120;i++);
}
}
void main()
{
P2 = 0xc0;
IE = 0x83;
TMOD = 0x00;
IT0 = 1;
IP = 0x02;
while(1)
{
while(K1==1);
while(K1==0);
TR0 = 1;
Tone_Index 滚悄春= 0;
while(Song[Song_Index][Tone_Index]!=-1&&K1==1&&TR0==1)
{
delay(300*Len[Song_Index][Tone_Index]);
Tone_Index++;
}
TR0 = 大耐0;
while(K1==0);
}
}
已经一具有一
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